Problema Solution
The larger of two consecutive integers is 11 more than one half the smaller. Find the integers
Answer provided by our tutors
let the two consecutive integers be: x and x+1
x + 1 in the larger since x + 1 > x
The larger of two consecutive integers is 11 more than one half the smaller:
x + 1 = 11 + (1/2)x
by solving we find:
x = 20
click here to see the step by step solution of the equation:
20 + 1 = 21
indeed
21 = 11 + 10 = 11 + (1/2)20
the two consecutive integers are 20 and 21.