Problema Solution
15. What is the vertex angle of an isosceles triangle whose equal sides are 15 meters long if the area is 112.5 square meters?
Answer provided by our tutors
The area of a triangle is given by the formula (1/2)absin(theta) where theta is the angle between sides a and b.
in this case a and b have equal length of 15
so (1/2)(15)(15)sin(theta)=112.5
sin(theta)=1
(theta) = 90 degrees