Problema Solution
How much of a 65-liter 91% hydrochloric acid solution must be removed and replaced with an equal amount of a 35% hydrochloric acid solution to lower its strength to 78%?
Answer provided by our tutors
let
x = liters of the 35% hydrochloric acid solution needed
0.91*(65 - x) + 0.35*x = 0.78*65
by solving we find:
x = 15.09 l
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15.09 liters of 91% hydrochloric acid solution must be removed and replaced with an equal amount of a 35% hydrochloric acid solution.