Problema Solution
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the speed. If 126 lb of force keeps a 1800-lb car from skidding on a curve of a radius 600 ft at 25 mph, what force would keep the same car from skidding on a curve radius 850 ft at 45 mph?
Answer provided by our tutors
let
F = the force
R= the radius of the curve
W = the weight of the car
V = the speed
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the speed:
F = k(W * V^2)/R, where k is constant
126 lb of force keeps a 1800-lb car from skidding on a curve of a radius 600 ft at 25 mph we have:
F = 126 lbs
W = 1800 lbs
R = 600 ft
V = 25 mph
126 = k(1800 * 25^2)/600
by solving we find k:
k = 0.0672
click here to see the step by step solution of the equation:
now we know that:
F = 0.0672(W * V^2)/R
R = 850 ft
V = 45 mph
W = 1800 lbs
F = 0.067(1800 * 45^2)/850
F = 287.31 lbs
click here to see the step by step solution of the equation: