Problema Solution

The perimeter of a rectangle is 110 ft. Find the width if the length is 5 less than twice the width.

Answer provided by our tutors

let


w = the width


l = the length


The perimeter of a rectangle is 110 ft:


2(l + w) = 110


the length is 5 less than twice the width


l = 2w - 5


by solving the system of equations:


2(l + w) = 110


l = 2w - 5


we find:


l = 35 ft


w = 20 ft


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the width is 20 feet.