Problema Solution
1.The width of a rectangular lot is 4 meters less than its length. If the perimeter of the lots is 76 meters, find the dimensions and the area of the lot.
Answer provided by our tutors
lenght= x
width= x-4
perimeter= 2(length +width)
76= 2(x+x-4)
38= 2x-4
42= 2x
x= 21.
so, length =21 cm, width = 17cm
so, dimension is 21 cm by 17 cm
area= 21*17 = 357 cm^2 is area....
done with the question.