Problema Solution

Which two consecutive numbers have squares that have a difference of 17?

Answer provided by our tutors

the two consecutive numbers can be written as: x and x+1


(x + 1)^2 - x^2 = 17


by solving we find:


x = 8


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8 + 1 = 9


indeed


9^2- 8 ^2 = 81 - 64 = 17


the two consecutive numbers are 8 and 9.