let

v = the rate of the truck, v>0

t = the time of the truck

v + 10 = the rate of the bus (a bus travels 10 kph faster than a truck)

t - 3 = the time of the bus (It travels 360 km in 3 hours less than the time required by the truck to travel the same distance)

d = 360 km the distance traveled by each vehicle

since distance = rate*time we have:

vt = 360

t = 360/v

(v + 10)(t - 3) = 360

plug t = 360/v into (v + 10)(t - 3) = 360

(v + 10)(360/v - 3) = 360

by solving we find:

v = 30 kph

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v + 10 = 10 + 10 = 40 kph

the rate of the truck is 30 kph.

the rate of the bus is 40 kph.