Problema Solution
find two consecutive even integers such that twice the s,aller exceeds the larger by 18.
Answer provided by our tutors
the two consecutive even integers can be written as:
2x, 2x + 2, where x is integer
twice the smaller exceeds the larger by 18:
2*2x = 2x + 2 + 18
by solving we find:
x = 10
click here to see the step by step solution of the equation:
2*10 = 20
2*20 + 2 = 22
the two consecutive even integers are 20 and 22.