Problema Solution

Two trains are 333 miles apart, and their speeds differ by 23 mph. Find the speed of each train if they are travelin toward each other and will meet in 3 hours.

Answer provided by our tutors

let


v = the speed of the slower train, v>0


v + 23 = the speed of the faster train


d = 333 mi the distance between them


t = 3 hr


since distance = speed*time we have:


vt + (v + 23)t = 333


3v + 3(v + 23) = 333


by solving we find:


v = 44 mph


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v + 23 = 44 + 23 = 67 mph


the speed of the slower train is 44 mph.


the speed of the faster train is 67 mph.