Problema Solution
An airplane climbs at a rate of 66.8 feet per minute. It descends at twice the rate that it climbs. Assuming it descends at a constant rate, how many feet will the airplane descend in 30 minutes?
Answer provided by our tutors
climbing rate: v1 = 66.8 ft/min
descending rate: v2 = 2*v1 = 2*66.8 ft/min (it descends at twice the rate that it climbs)
the time of the airplane's descending: t = 30 min
the length of the descending: d = v2*t (distance = avg.speed*time)
d = 2*66.8*30
d = 4008 ft
in 30 min the airplane will descend 4008 feet.