Problema Solution
a pool measuring 20 meters by 28 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 1428 square meters, what is the width of the path?
Answer provided by our tutors
let
x = the width of the path, x>0
w = 20 m the width of the pool
l = 28 m the length of the pool
the width of the pool together with the path is: w + 2x
the length of the pool together with the path is: l + 2x
the are of the pool and the path combined is: (w + 2x)(l + 2x)
(w + 2x)(l + 2x) = 1428
(20 + 2x)(28 + 2x) = 1428
by solving we find:
x = 7 m
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the path is 7 meters width.