Problema Solution
a chemist wishes to strengthen a mixture that is 10% alcohol to one that is 30% alcohol. How much pure alcohol should be added to 12L of the 10% mixture?
Answer provided by our tutors
let
x = liters of pure alcohol to be added
0.10*12 + 1.00*x = 0.30*(12 + x)
by solving we find:
x = 3.43 L
click here to see the step by step solution of the equation:
approximately 3.43 liters of pure alcohol should be added to the mixture.