Problema Solution
Solution A is 50% hydrochloric acid, while solution B is 75% hydrochloric acid. How many liters of each solution should be used to make 100 liters of a solution which is 60% hydrochloric acid?
Answer provided by our tutors
let
x = liters of solution A
y = liters of solution B
x + y = 100
0.50x + 0.75y = 0.60*100
by solving the above system of equations we find:
x = 60 l
y = 40 l
click here to see the step by step solution of the system of equations:
60 liters of solution A should be mixed with 40 liters of solution B.