Problema Solution

A student ran the 50yd dash in 5.8 sec. At what speed did the student run in miles per hour?

Answer provided by our tutors

1760 yd = 1 mi


1 yd = (1/1760) mi


3600 sec = 1 hr


1 sec = 1/3600 hr


d = 50 yd = 50(1/1760) mi


t = 5.8 sec = 5.8(1/3600) hr


v = d/t the average speed


v = (50(1/1760))/(5.8(1/3600))


by solving we find:


v = 17.63 mph


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the student ran with a speed of 17.63 mph.