Problema Solution
The length of the base of an isosceles triangle is one fourth the length of one of its legs. If the perimeter of the triangle is 50 inches , what is the length of the base ?
Answer provided by our tutors
let
b = the length of the base
a = the length of one of the legs
the length of the base of an isosceles triangle is one fourth the length of one of its legs:
b = (1/4)a
the perimeter of the triangle is 50 inches:
2a + b = 50
by solving the system of equations:
b = (1/4)a
2a + b = 50
we find:
a = 22.2 in
b = 5.5 in
click here to see the step by step solution of the system of equations:
the length of the base is 5.5 inches approximately.