Problema Solution
How many different isosceles triangles can you find that have sides that are whole-numbered lengths and that have a perimeter of 18?
Answer provided by our tutors
let
a = the length of one leg, a is integer, a >0
b = the length of the base, b is integer, b >0
using the triangle inequality we get:
2a > b > 0
the perimeter is 18:
2a + b = 18
b = 18 - 2a
b > 0
18 - 2a > 0
18 > 2a
9 > a
plug b = 18 - 2a into 2a>b:
2a > 18 - 2a
4a > 18
a > 18/4
a > 4
now we know that 4 < a < 9:
for a = 5, b = 18 - 2*5 = 8
for a = 6, b = 18 - 2*6 = 6
for a = 7, b = 18 - 2*7 = 3
for a = 8, b = 18 - 2*8 = 2
there are 4 different isosceles triangles.