Problema Solution

How many different isosceles triangles can you find that have sides that are whole-numbered lengths and that have a perimeter of 18?

Answer provided by our tutors

let


a = the length of one leg, a is integer, a >0


b = the length of the base, b is integer, b >0


using the triangle inequality we get:


2a > b > 0


the perimeter is 18:


2a + b = 18


b = 18 - 2a


b > 0


18 - 2a > 0


18 > 2a


9 > a


plug b = 18 - 2a into 2a>b:


2a > 18 - 2a


4a > 18


a > 18/4


a > 4


now we know that 4 < a < 9:


for a = 5, b = 18 - 2*5 = 8


for a = 6, b = 18 - 2*6 = 6


for a = 7, b = 18 - 2*7 = 3


for a = 8, b = 18 - 2*8 = 2


there are 4 different isosceles triangles.