Problema Solution

A chemist needs 12 liters of a 40% alcohol solution. She must mix a 20% alcohol solution and a 50% alcohol solution to obtain what she needs. How many liters of each will be required to obtain what is needed?

Answer provided by our tutors

let


x = liters of the 20% alcohol solution


y = liters of the 50% alcohol solution


A chemist needs 12 liters of a 40% alcohol solution:


x + y = 12


0.20x + 0.50y = 0.40*12


by solving the system of equations we find:


x = 4 liters


y = 8 liters


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4 liter of the 20% alcohol solution and 8 liters of the 50% alcohol solution are required.