Problema Solution
An object is thrown, and it follows a parabolic path. Its height, in meters, is given by the function f(x) = -x^2+3x+6 Find the maximum height that the object may reach
Answer provided by our tutors
we need to find the maximum of the parabolic function: f(x) = -x^2+3x+6
The quotient in front of x^2 is -1<0 follows the function has a maximum:
f max = c - (b^2)/(4a), where a = -1. b = 3, c = 6
f max = 6 - (3^2)/(4*(-1))
f max = 6 + 9/4
f max = 8.25 m
the maximum height that the object may reach is 8.25 meters.