Problema Solution
Find the dimensions of a rectagular lot if the perimeter is 40 meter and the area is 96 meter.
Answer provided by our tutors
Let side = x
let width = y
perimeter = 2(x+y) = 40
also
area = xy = 96
=> x+y = 20 and xy = 96
=> (x+y)^2-4xy = (x-y)^2 => 400-384 => (x-y)^2 = 16=> x-y = 4
=> adding x+y = 20 and x-y = 4 we get
2x = 24 => x = 12
and y = 8