Problema Solution
A private plane traveled from Seattle to a rugged wilderness, at an average speed of 156 mph. On the return trip, the average speed was 182 mph. If the total traveling time was 4 hours, how far is Seattle from the wilderness?
Answer provided by our tutors
let
d = the distance from Seattle to a rugged wilderness
v1 = 156 mph the avg.speed traveling to the wilderness
t1 = the time of the trip to the wilderness
v2 = 182 mph the avg. speed traveling back to Seattle
t2 = the time of the trip back to Seattle
the total traveling time was 4 hours:
t1 + t2 = 4
since speed = distance/time follows time = distance/speed thus
t1 = d/v1
t1 = d/156
t2 = d/v2
t2 = d/182
plug t1 = d/156 and t2 = d/182 into t1 + t2 = 4:
d/156 + d/182 = 4
by solving we find:
d = 336 mi
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Seattle is 336 miles far from the wilderness.