Problema Solution
find the vertex of a graph of a quadratic relation y =3x^2 +12x -15
Answer provided by our tutors
The following "vertex formula" will give us the x coordinate for the vertex of the parabola:
Given a quadratic function: ax^2 + bx + c the x coordinate of the vertex is: x = -b/2a
In our case a = 3, b = 12, c = -15. Lets plug these values in the formula:
x = -12/(2*3)
x = - 2
the y coordinate of the vertex is:
y = 3*(-2)^2 + 12*(-2) - 15
y = -27
the vertex is (-2, -27)
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