Problema Solution
In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took hour longer. How far did she travel to the appointment?
Answer provided by our tutors
let
v1 = 50 mph the avg. speed on the way to the appointment
t1 = the time of the trip to the appointment
v2 = 40 mph the avg. speed on the return trip
t2 = the time of the trip back
d = distance of the trip
since speed = distance/time follows time = distance/speed
t1 = d/v1
t2 = d/v2
The return trip took hour longer:
t2 = t1 + 1
plug t1 = d/v1 and t2 = d/v2 into the last equation:
d/v2 = d/v1 + 1
d/40 = d/50 + 1
by solving we find:
d = 200 mi
click here to see the step by step solution of the equation:
May traveled 200 miles to the appointment.