Problema Solution
Every weekend you ride your bike on a forest preserve path. The path is 24 miles long and ends at a waterfall, at which point you relax and then make the trip back to the starting point. one weekend, you find that in the same time it takes you to travel to the waterfall, you are only able to return 16 miles. your average speed going to the waterfall is 4 miles per hour faster than the return trip. What was your averages speed going to the waterfall?
Answer provided by our tutors
let
v = the average speed of the return trip
v + 4 = the average speed going to the waterfall (average speed going to the waterfall is 4 miles per hour faster than the return trip)
d1 = 24 mi the distance to the waterfall
t = the time of the travel to the waterfall
d2 = 16 min the distance u travel back in time t
since average speed = distance/time follows time = distance/average speed:
t = d1/(v + 4)
t = 24/(v + 4)
in the same time it takes you to travel to the waterfall, you are only able to return 16 miles:
t = 16/v
now we have:
24/(v + 4) = 16/v
by solving we find:
v = 8 mph
click here to see the step by step solution of the equation:
v + 4 = 8 + 4 = 12 mph
the average speed going to the waterfall was 12 mph.