Problema Solution
how much of a 50% alcohol solution must be mixed with 70 gallons of a 22% alcohol solution to obtain a solution that is 40% alcohol?
Answer provided by our tutors
let
x = gal of 50% alcohol solution
0.50x + 0.22*70 = 0.40(x + 70)
by solving we find:
x = 126 gal
click here to see the step by step solution of the equation:
126 gallons of 50% alcohol solution must be used for the mix.