Problema Solution
A person can give 3 trial exams for the clearing test. In 1st attempt probability of passing is 40 , Those who have
failed have 60 probability of passing the exam in 2nd attempt. Those who have failed in 2nd attempt have
20 probability of passing the exam
Find probability
1. of passing either in 1st or 2nd attempt
2. of passing in 2nd
attempt
3. of passing in 3rd attempt
Answer provided by our tutors
you need to draw a tree diagram (at the moment we don't have the option to draw) and use to find the solutions:
1. P (passing either in 1st or 2nd attempt) = 0.40 + 0.60*0.60 = 0.40 + 0.36 = 0.76 or 76%
2. P (passing in 2nd attempt) = 0.60*0.60 = 0.36 or 36%
3. P (passing in 3rd attempt) = 0.60*0.40*0.20 = 0.048 or 4.8%