Problema Solution
a circle is inscribed in a square. If the perimeter of the square exceeds the circumference of the circle by 10 units, what is the measure of the side of the square?
Answer provided by our tutors
make a drawing
let 'a' represent the measure of the side of the square
the length of the side of the square is equal to the diameter of the square
the perimeter of the square is: P1 = 4a
the circumference of the circle is: P2 = a*pi (since the circumference of the circle is diameter x pi, and in our case the diameter = a)
the perimeter of the square exceeds the circumference of the circle by 10 units:
P1 = 10 + P2
4a = 10 + a*pi
4a - a*pi = 10
a(4 - pi) = 10
a = 10/(4 - pi)
pi = 3.14
a = 10/(4 - 3.14)
a = 11.63 units
the measure of the side of the square is 11.63 units.