Problema Solution

a circle is inscribed in a square. If the perimeter of the square exceeds the circumference of the circle by 10 units, what is the measure of the side of the square?

Answer provided by our tutors

make a drawing


let 'a' represent the measure of the side of the square


the length of the side of the square is equal to the diameter of the square


the perimeter of the square is: P1 = 4a


the circumference of the circle is: P2 = a*pi (since the circumference of the circle is diameter x pi, and in our case the diameter = a)


the perimeter of the square exceeds the circumference of the circle by 10 units:


P1 = 10 + P2


4a = 10 + a*pi


4a - a*pi = 10


a(4 - pi) = 10


a = 10/(4 - pi)


pi = 3.14


a = 10/(4 - 3.14)


a = 11.63 units


the measure of the side of the square is 11.63 units.