Problema Solution

The area of a table top is 57 square feet, and twice the length is 5 feet shorter than four times the width. Find the perimeter of the table top.

Answer provided by our tutors

we will assume the table is rectangular


let


l = the length of the table top


w = the width of the table top


the area of a table top is 57 square feet:


l*w = 57


twice the length is 5 feet shorter than four times the width:


2l = 4w - 5


l = (1/2)(4w - 5)


we need to find the perimete: P = 2(l + w)


plug l = (1/2)(4w - 5) into l*w = 57:


(1/2)(4w - 5)w = 57


by solving we find:


w = 6 ft


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l = (1/2)(4*6 - 5)


l = 9.5 ft


the perimeter is:


P = 2(9.5 + 6)


P = 31 ft


the perimeter of the table top is 31 feet.