Problema Solution
Jason left Detroit, and 3 hours later, Dan left going 89 mph faster to catch up. After 2 hours, Dan caught up. Find Jason's average speed.
Answer provided by our tutors
let
v1 = Jason's average speed
t1 = the time of the travel of Jason
v2 = 89 mph Dan's average speed
t2 = 2 hr the time of Dan's travel
Since Dan left 3 hours later we have
t1 = t2 + 3
t1 = 2 + 3
t1 = 5 hr
since they both traveled the same distance and distance = speed*time we have:
v1*t1 = v2*t2
v1*5 = 89*2
by solving we find:
v1 = 35.6 mph
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Jason's average speed was 35.6 mph.