Problema Solution
House A is twice as old as house B. 9 years ago house A was three times as old as House b. How old are the houses now?
Answer provided by our tutors
let
a = the age of house A now
b = the age of house B now
House A is twice as old as house B:
a = 2b
9 years ago house A was three times as old as House B:
a - 9 = 3(b - 9)
by solving the system of equations:
a = 2b
a - 9 = 3(b - 9)
we find:
a = 36 years
b = 18 years
click here to see the step by step solution of the system of equations:
House A is 36 years old now.
House B is 18 years old now.