Problema Solution
A rectangle has an area of 1144 in^2 and a perimeter of 148 in. Find its dimensions and the longest length.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
A = 1144 in^2 the area of the rectangle
P = 148 in the perimeter of the rectangle
A = l*w thus
l*w = 1144
P = 2(l + 2) thus
2(l + w) = 148 divide both sides by 2
l + w = 74
w = 74 - l
plug w = 74 - l into l*w = 1144
l(74 - l) = 1144
by solving we find:
l1 = 52 in
l2 = 22 in
click here to see the step by step solution of the equation:
w = 74 - 52
w = 22 in
the length is 52 in and the width is 22 in.