Problema Solution
how many gallons of pure alcohol should be mixed with 20 gallons of 15% alcohol to get a mixture that is 25% alcohol?
Answer provided by our tutors
let
x = gal of pure 100% alcohol
1.00x + 0.15*20 = 0.25*(x + 20)
by solving we find:
x = 2.67 gal
click here to see the step by step solution of the equation:
2.67 gallons of pure alcohol is needed for the mix.