Problema Solution
How many gallons of a 80% alcohol solution must be mixed with 30 gallons of a 24% solution to obtain a solution that is 70% alcohol?
Answer provided by our tutors
let
x = gallons of a 80% alcohol solution needed for the mix
0.80x + 0.24*30 = 0.70(x + 30)
by solving we find:
x = 138 gal
click here to see the step by step solution of the equation:
138 gallons of a 80% alcohol solution must be used in the mix.