Problema Solution
The square of a positive number is a 47 less than twice the square of the next consecutive positive number. What are the numbers?
Answer provided by our tutors
let 'x' represent the positive number, x>0
x + 1 is the next consecutive positive number
x^2 = 2(x+1)^2 - 47
by solving we find:
x = 5
click here to see the step by step solution of the equation:
x + 1 = 5 + 1 = 6
the numbers are 5 and 6.