Problema Solution
A population of bacteria is growing according to the equation P(t)=1600e0.21t , with t measured in years. Estimate when the population will exceed 7569.
Answer provided by our tutors
P(t) = 1600e^(0.21t)
we need to find t such that P(t) = 7569 or:
1600e^(0.21t) = 7569
e^(0.21t) = 7569/1600
0.21t = ln(7569/1600)
t = (1/0.21)*(ln(7569/1600))
t = 7.4 years approximately
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in 7.4 years the population will exceed 7569 bacteria.