Problema Solution
A woman paid $2.25 for some apples, bananas, and pears. The apples cost $.10 each, the pears cost $.20 each, and the bananas cost $.25 each. The number of apples was equal to the number of pears and bananas combined. How many of each did she buy?
Answer provided by our tutors
let
a = the number of apples, a>0
b = the number of bananas, b>0
p = the number of pears, p?
a,b and p are integer
0.10a + 0.20b + 0.25p = 2.25 divide by 0.05
2a + 4b + 5p = 45
the number of apples was equal to the number of pears and bananas combined:
a = p + b
plug a = p + b into 2a + 4b + 5p = 45:
2(p + b) + 4b + 5p = 45
6b + 7p = 45
b = (45 - 7p)/6
for p = 3
b = (45 - 3*7)/6
b = 4 bananas
a = 3 + 4
a = 7 apples
the solutions is: 7 apples, 4 bananas and 3 pears.