Problema Solution
FIND TWO NUMBERS IF THREE TIMES THE SECOND NUMBER EXCEEDS SEVEN TIMES THE FIRST BY 3.FIVE TIMES THE FIRST INCREASED BY ONE IS EQUAL TO TWICE THE SECOND
Answer provided by our tutors
let 'x' and 'y' represent the numbers
3 TIMES THE SECOND NUMBER EXCEEDS 7 TIMES THE FIRST BY 3:
3y = 7x + 3
5 TIMES THE FIRST INCREASED BY 1 IS EQUAL TO TWICE THE SECOND:
5x + 1 = 2y
by solving the system of equations:
3y = 7x + 3
5x + 1 = 2y
we find:
x = 3
y = 8
click here to see the step by step solution of the system of equations:
the two numbers are 3 and 8.