Problema Solution
The length of a rectangular garden exceeds the width by 10ft. If the perimeter is 48ft, what are its dimensions?
Answer provided by our tutors
let
x = the length, x>0
y = the width, y>0
the length of a rectangular garden exceeds the width by 10 ft:
y = 10 + y
the perimeter is 48 ft:
2(x + y) = 48 divide both sides by 2
x + y = 24
by solving the system of equations:
x = 10 + y
x + y = 24
we find:
x = 17 ft
y = 7 ft
click here to see the step by step solution of the system of equations:
the dimensions of the rectangle are 17 ft and 7 ft.