Problema Solution

The length of a rectangular garden exceeds the width by 10ft. If the perimeter is 48ft, what are its dimensions?

Answer provided by our tutors

let


x = the length, x>0


y = the width, y>0


the length of a rectangular garden exceeds the width by 10 ft:


y = 10 + y


the perimeter is 48 ft:


2(x + y) = 48 divide both sides by 2


x + y = 24


by solving the system of equations:


x = 10 + y


x + y = 24


we find:


x = 17 ft


y = 7 ft


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the dimensions of the rectangle are 17 ft and 7 ft.