Problema Solution

the winner of a 2-mile bicycle race finishes 2 minutes ahead of a teammate and travels, on average, 2 miles per hour faster than the teammate. find the average speed per racer.

Answer provided by our tutors

let


d = 2 mi is the distance of the race


v = the average speed of the slower teammate


v + 2 = the average speed of the winner, v>0


t = the time of the slower teammate


t - 2/60 = the time of the winner


since speed = distance/time we have:


for the slower teammate


v = d/t


v = 2/t


t = 2/v


for the winner:


v + 2 = 2/(t - 2)


plug t = 2/v into the last equation:


v + 2 = 2/(2/v - 2)


by solving we find:


v = 0.73 mph


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v + 2 = 0.73 + 2 = 2.73 mph


the average speed of the winner is 2.73 mph.


the average speed of the teammate is 0.73 mph.