Problema Solution
A cashier has a total of 30 bills, made up of ones, fives, and twenties. The number of twenties is 9 more than the number of ones. The total value of the money is $351. How many of each denomination of bills are there? (Hint: Let x = the number of ones, y = the number of fives, and z = the number of twenties)
Answer provided by our tutors
Let
x = the number of ones,
y = the number of fives, and
z = the number of twenties
A cashier has a total of 30 bills, made up of ones, fives, and twenties:
x + y + z = 30
The number of twenties is 9 more than the number of ones:
z = 9 + x
The total value of the money is $351:
x + 5y + 20z = 351
by solving the system of equations:
x + y + z = 30
z = 9 + x
x + 5y + 20z = 351
we find:
x = 6
y = 9
z = 15
click here to see the step by step solution of the system of equations:
there 6 one dollar bills, 9 five dollar bills and 15 twenty dollar bills.