Problema Solution
What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300 ml of a 50% solution?
Answer provided by our tutors
let
x = ml of the 60% acid solution
y = ml of the 30% solution
the mix is 300 ml of a 50% solution:
x + y = 300
0.60x + 0.30y = 0.50*300
by solving the above system of equations we find:
x = 200 ml
y = 100 ml
click here to see the step by step solution of the system of equations:
200 ml of 60% acid solution must be mixed with 100 ml of 30% solution.