Problema Solution
The length of a rectangle is six times its width.
If the perimeter of the rectangle is 140 yd, find its area.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
P = 140 yd the perimeter of the rectangle
A = l*w the area of the rectangle
the length of a rectangle is six times its width:
l = 6w
the perimeter P = 2(l + w)
2(l + w) = 140
by solving the system of equations:
l = 6w
2(l + w) = 140
we find:
l = 60 yd
w = 10 yd
click here to see the step by step solution of the equations:
A = 60*10
A = 600 yd^2
the area of the rectangle is 600 yd^2.