Problema Solution
A ball is thrown downward from the top of a 180 foot building with an initial velocity of 20 feet per second. The height (h) after (T) seconds is given by the equation h=-16t^2 -20t +180. How long after the ball is thrown willl it reach the ground
Answer provided by our tutors
the ball will reach the ground when h = 0 for some t, t>0 (the time can not be negative)
by solving the equation:
-16t^2 -20t +180 = 0
we find
t = 2.79 sec
click here to see the step by step solution of the equation:
the ball will reach the ground in 2.79 seconds.