Problema Solution

The length of a rectangle is 2 more than the width and the perimeter is 80. Find the dimensions of the rectangle.

Answer provided by our tutors

let


l = the length of the rectangle


w = the width of the rectangle


the length of a rectangle is 2 more than the width:


l = 2 + w


the perimeter is 80:


2(l + w) = 80


by solving the system of equations:


l = 2 + w


2(l + w) = 80


we find:


l = 21


w = 19


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the dimensions of the rectangle are: the length is 21 and the width is 19.