Problema Solution
find x so that x,x+2,x+b are consecutive terms of a geometric progression.
Answer provided by our tutors
any three consecutive terms a, b and c of geometric progression will satisfy the following equation:
b^2=ac
where b is considered to be the geometric mean between a and c.
in our case we have
(x + 2)^2 = x(x + b)
by solving for x we find:
x = 4/(b - 4)
click here to see the step by step solution of the equation:
x + 2 = 4/(b - 4) + 2 = (4 + 2b - 8)/(b - 4) = (2b - 4)/(b - 4) = 2(b - 2)/(b - 4)
x + b = 4/(b - 4) + b = (4 + b^2 - 4b)/(b - 4) = (b^2 - 4b + 4)/(b - 4) = (b - 2)^2/(b - 4)
the three terms of the geometric progression are: 4/(b - 4), 2(b - 2)/(b - 4) and (b - 2)^2/(b - 4).