Problema Solution
How much 10% acis must be mixed with 20% acid to obtain 80 ml of 12% acid?
Answer provided by our tutors
let
x = ml of 10% acid
y = ml of 20% acid
we have to obtain 80 ml of 12% acid thus we have:
x + y = 80
0.10x + 0.20y = 0.12*80
by solving the above system of equations we find:
x = 16 ml
y = 64 ml
click here to see the step by step solution of the system of equations:
16 ml of 10% acid and 64 ml of 20% acid are needed.