Problema Solution
ABCD is a square inscribed in circle. P is any point on minor arc AB. Prove that PD and PC trisect angle APB
Answer provided by our tutors
make a drawing and use the theorem: Periphery angles over the same arc are equal.
the angles APD, DPC and CPB are equal as periphery angles over arcs with same lengths
follows PD and PC trisect angle APB.