Problema Solution
The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
The perimeter of a rectangle is 160 ft:
2(l + w) = 160
One fourth the length is the same as twice the width:
(1/4)l = 2w
by solving the system of equations:
2(l + w) = 160
(1/4)l = 2w
we find:
l = 71.11 ft
w = 8.89 ft
click here to see the step by step solution of the system of equations:
the dimensions of the rectangle are: the length is 71.11 ft and the width is 8.89 ft.