let

x = the first number

y = the second number

One number is 4 less than 3 times a second number:

x = 3y - 4

If 3 more than two times the first number is decreased by two times the second, the result is 11:

3 + 2x - 2y = 11

by solving the system of equations:

x = 3y - 4

3 + 2x - 2y = 11

we find:

x = 8

y = 4

click here to see the step by step solution of the system of equations:

the two numbers are 8 and 4.