Problema Solution
Find the dimensions of a rectangle whose perimeter is 40 and whose area is 96.
Answer provided by our tutors
let
w = the width of the triangle, w>0
l = the length of the triangle, l>0
the perimeter is 40 means:
2(l + w) = 40 divide both sides by 2
l + w = 20
l = 20 - w
the area is 96 means:
l*w = 96
plug l = 20 - w into the last equation:
(20 - w)*w = 96
by solving we find:
w1 = 8
w2 = 12
click here to see the step by step solution of the equation:
for w = 8 we have l = 20 - 8 = 12
for w = 12 we have l = 20 - 12 = 8
the dimensions of the rectangle are 8 and 12.