Problema Solution

Find the dimensions of a rectangle whose perimeter is 40 and whose area is 96.

Answer provided by our tutors

let


w = the width of the triangle, w>0


l = the length of the triangle, l>0


the perimeter is 40 means:


2(l + w) = 40 divide both sides by 2


l + w = 20


l = 20 - w


the area is 96 means:


l*w = 96


plug l = 20 - w into the last equation:


(20 - w)*w = 96


by solving we find:


w1 = 8


w2 = 12


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for w = 8 we have l = 20 - 8 = 12


for w = 12 we have l = 20 - 12 = 8


the dimensions of the rectangle are 8 and 12.